A steel ball is dropped onto a hard floor from a height of 1 50 m and rebounds to a height of 1 45 m.
A ball is dropped 1 m to the floor.
The ball bounces off of the floor and during the bounce 0 60 j of energy is dissipated.
A ball is dropped on a floor from a height of 2 m.
A ball is dropped on the floor from a height of 10 m rebounds to a height of 2 5 m.
A rubber ball with a mass 0 20 kg is dropped vertically from a height of 1 5 m above the floor.
While the magnitude and the direction of the impulse of the net force applied to the ball during the collision with the floor.
A 0 5 kg ball is dropped from rest at a point 1 20 m above the floor.
Heat capacity of the ball is 800 j k 1.
The ball rebounds straight upward to a height of 0 7 m.
Calculate the average force the floor exerts on the ball.
A ball is dropped on a floor from a height of 2 0 m.
Assuming that 2 0 of mechanical energy is lost in the form of thermal energy.
A determine the magnitude and direction of the impulse delivered to the ball by the floor.
Calculate the rise in the temperature of the ball in the collision.
A 4 28 n s upward b 4 28 n s downward c 8 56 n s upward d 8 56 n s downward.
After a 0 300 kg rubber ball is dropped from a height of 1 75 m it bounces off a concrete floor and rebounds to a height of 1 50 m.
After the collision it rises up to a height of 1 5 m.
If the ball is in contact with the floor for 0 02 sec its average acceleration during contact is.
After the collision it rises upto a height of 1 m.
If the specific heat capacity of the ball is 8 0 0 j k then the rise in temperature of the ball during collision is take g 1 0 m s 2.
B suppose the ball is in contact with the floor for 0 05 s.